The principle, precisely stated
Archimedes' principle says that a body wholly or partly submerged in a fluid experiences an upward buoyant force equal to the weight of the fluid it displaces. As a formula, the buoyant force is
F_b = ρ_fluid × V_displaced × g where ρ_fluid = density of the fluid, V_displaced = submerged volume, g = gravitational acceleration
That is the entire law. It says nothing about the shape of the object, its own density, or the depth it sits at — only the volume of fluid it physically pushes aside. A cube, a sphere and a ship hull of equal submerged volume in the same fluid feel exactly the same upward push.
Why it works: pressure increases with depth
The principle follows directly from hydrostatic pressure. Pressure in a fluid at rest grows linearly with depth, P(h) = P_0 + ρ g h, because each layer of fluid has to support the weight of everything above it. A submerged object therefore has fluid pushing on it harder from below than from above — the bottom face sits deeper, so it feels a larger pressure than the top face. Integrate that pressure difference over the object's entire surface and, remarkably, the sideways components all cancel by symmetry while the vertical components sum to exactly the weight of the displaced fluid. Buoyancy is not a separate force bolted onto the physics; it is what net hydrostatic pressure looks like once you add it all up.
Floating, sinking, and the density ratio
Compare the buoyant force to the object's own weight, W = ρ_object × V_object × g. If the object is fully submerged, V_displaced equals its own volume, so the ratio of forces is exactly the density ratio ρ_object / ρ_fluid. Three cases follow directly. If ρ_object < ρ_fluid, the fully submerged buoyant force already exceeds the weight, so the object rises and settles floating with only a fraction submerged — that fraction is precisely ρ_object / ρ_fluid, which is why an ice cube (ρ ≈ 0.92 g/cm³) floats in water with about 92% of its volume underwater and only 8% showing. If ρ_object = ρ_fluid, the two forces balance at any depth and the object is neutrally buoyant, drifting wherever it is placed. If ρ_object > ρ_fluid, buoyancy can never catch up and the object sinks to the bottom.
Why steel ships float
Steel is roughly eight times denser than water, yet steel ships float, because Archimedes' principle cares about the average density of the whole hull, not the density of the material it is made from. A hull shaped as a hollow shell displaces a volume of water far larger than the volume of steel used to build it; as long as the ship's total weight (steel plus cargo plus the air inside) divided by its total submerged volume stays below the water's density, it floats, with the hull sinking exactly deep enough that the displaced water's weight matches the ship's weight. Load more cargo and the ship simply sits lower in the water, displacing more, until balance is restored — up to the point where the hull is fully submerged and can sink no lower without water breaching the deck.
Changing the fluid changes the answer
Because the law depends on the fluid's density as much as the object's, the same object floats differently in different fluids. Swap water for vegetable oil (ρ ≈ 0.92 g/cm³) and objects that floated high in water now sit far lower, or sink outright if their own density exceeds the oil's. Swap in mercury (ρ ≈ 13.5 g/cm³) and a solid iron block, which sinks instantly in water, floats on mercury with most of its volume above the surface, because iron at ρ ≈ 7.9 g/cm³ is still less than half as dense as mercury. This simulation lets you swap the fluid and watch exactly that: the same object, the same principle, a different equilibrium depth.
Frequently asked questions
Does Archimedes' principle depend on the shape of the object?
No. The buoyant force depends only on the density of the fluid and the volume of fluid displaced, not on the shape, material or orientation of the submerged object. Two differently shaped objects that displace equal volumes feel equal buoyant forces.
Why does a steel ship float when steel itself sinks in water?
Buoyancy responds to the average density of the entire hull, including the air-filled space inside it, not the density of the steel plate alone. A hollow hull displaces far more water than the volume of steel used to build it, so the ship's total weight divided by its submerged volume stays below water's density even though steel alone would sink.
What fraction of an iceberg is underwater?
For a fully floating object the submerged fraction equals its own density divided by the fluid's density. Ice at about 0.92 g/cm³ floating in seawater at about 1.025 g/cm³ gives a submerged fraction of roughly 90%, which is the origin of the phrase ‘tip of the iceberg’.
Try it live
Everything above runs in your browser — open Archimedes' Principle and change the parameters while it is running. Nothing is installed, nothing is uploaded, the whole model lives in one tab.
▶ Open Archimedes' Principle simulation