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Le Chatelier's Principle: How Equilibria Fight Back

Push a reaction at equilibrium with more reactant, more heat or more pressure, and it shifts to partially undo the disturbance — here's why, reaction by reaction.

mysimulator teamUpdated June 2026≈ 6 min read▶ Open the simulation

A system pushed away from equilibrium pushes back

Henri Le Chatelier stated the principle in 1884: if a system at chemical equilibrium is subjected to a change in concentration, temperature, volume or pressure, the equilibrium shifts in the direction that partially counteracts the imposed change. It's not a new law of physics — it's a consequence of equilibrium thermodynamics, but it's a remarkably reliable shortcut for predicting which way a reaction will shift without doing any calculation at all.

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Concentration: Q versus K

At equilibrium, the reaction quotient Q equals the equilibrium constant K. Add more of a reactant and Q instantly drops below K (more reactant relative to product than equilibrium calls for), so the reaction proceeds forward — consuming reactant and producing product — until Q climbs back to K. Add more product instead and Q jumps above K, so the reaction runs in reverse until Q falls back down. Nothing about K itself changes; only the concentrations shift until the same ratio is restored.

Temperature: heat as a reactant or product

Temperature is the one perturbation that actually changes K itself, not just the concentrations, because K is temperature-dependent (via the van't Hoff relation, ΔG° = −RT·lnK, and ΔG° itself varies with T). The intuitive trick is to treat heat as a participant in the reaction: for an exothermic reaction, write heat as a product (A + B ⇌ C + heat); adding heat (raising T) then shifts equilibrium left, back toward reactants, exactly as adding more of any other product would. For an endothermic reaction, heat behaves as a reactant, and raising T shifts equilibrium right, toward products. The Haber process (N₂ + 3H₂ ⇌ 2NH₃, exothermic) is the classic industrial illustration: higher temperature speeds up the reaction kinetically but actually lowers the equilibrium ammonia yield, which is exactly why industrial Haber plants run at a compromise temperature — hot enough for a usable reaction rate, not so hot that equilibrium yield collapses.

Pressure and volume: only matters when moles of gas change

Compressing the volume of a gas-phase system raises every gas's concentration/partial pressure simultaneously, and the system responds by shifting toward whichever side has fewer moles of gas, since that reduces the total mole count and partially counteracts the pressure increase. In the Haber process, 4 moles of gas (1 N₂ + 3 H₂) become 2 moles of gas (2 NH₃), so compressing the system shifts equilibrium toward more ammonia — this is exactly why high pressure is the other lever industrial ammonia synthesis uses. Critically, if the total moles of gas are equal on both sides of a reaction, pressure changes affect the rate at which equilibrium is reached but don't shift the equilibrium position at all, since compressing both sides by the same factor leaves Q/K unchanged.

N₂(g) + 3H₂(g) ⇌ 2NH₃(g) + heat     (exothermic, 4 mol gas → 2 mol gas)
  add N₂ or H₂   → shifts right (more NH₃)
  remove NH₃      → shifts right
  raise T          → shifts left  (K decreases)
  raise P (compress) → shifts right (fewer gas moles that side)

A catalyst is the one thing that changes nothing here

A catalyst speeds up both the forward and reverse reactions equally, so it gets the system to equilibrium faster but never changes where that equilibrium sits — K is unaffected. This trips people up because catalysts are so central to industrial chemistry (the Haber process itself relies on an iron catalyst), but their entire job is kinetic, not thermodynamic: getting to the same destination sooner, not choosing a different destination.

Frequently asked questions

Does adding a catalyst shift an equilibrium?

No. A catalyst lowers the activation energy for both the forward and reverse reactions equally, speeding up how quickly equilibrium is reached, but it doesn't change the equilibrium constant K or the final equilibrium concentrations at all — only reaction rate is affected, not equilibrium position.

Why does raising temperature lower the ammonia yield in the Haber process even though the reaction is faster?

The Haber process is exothermic, so by Le Chatelier's logic, adding heat is like adding a product, and the equilibrium shifts back toward reactants (N2 and H2), lowering K and the equilibrium yield of NH3. Higher temperature does speed up how quickly equilibrium is reached, which is a separate, purely kinetic effect — industrial plants balance the two by running at a moderate compromise temperature.

Why doesn't pressure affect every gas-phase equilibrium?

Compressing the system only shifts the equilibrium position if the number of gas moles differs between reactants and products, since only then does shifting toward one side actually reduce the total mole count and relieve the pressure increase. If both sides have equal moles of gas, compression raises all concentrations proportionally, leaving the reaction quotient Q unchanged relative to K, so the equilibrium position doesn't move even though the system reaches it faster.

Try it live

Everything above runs in your browser — open Le Chatelier Principle Simulator and change the parameters while it is running. Nothing is installed, nothing is uploaded, the whole model lives in one tab.

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