Physics Electrostatics GCSE � A-Level � IB � AP ●●○ Intermediate Free

Electric Field Lines Simulator

Place point charges and watch field lines and equipotentials form in real time � Coulomb's law made visible.

|E| at cursor 0.00 N/C
V at cursor 0.00 V
Charges 0 total
Net charge 0 nC

Place Charges

Type
Magnitude 5 nC
Action

Display Options

Field lines
Equipotentials
Potential map
Force arrows

Presets

Controls: Click canvas ? place charge  |  Drag ? move charge  |  Right-click ? remove charge  |  C clear all  |  E equipotentials  |  L field lines

Understanding Electric Fields

Coulomb's Law

The force between two point charges: F = kq1q2/r� where k = 8.99�10? N�m�/C�. Force is repulsive for like charges (both positive or both negative) and attractive for opposite charges. Force doubles when charge doubles; quadruples when separation halves.

Electric Field Strength

The electric field E at any point is the force per unit positive charge: E = F/q = kQ/r�. It is a vector � pointing away from positive charges, toward negative charges. The field tells you the force a charge would experience without needing to place a real charge there.

Superposition Principle

When multiple charges are present, the total field is the vector sum of individual contributions: E_total = Skq?r?^/r?�. Similarly, electric potential is a scalar sum: V_total = Skq?/r?. This is why dipole fields look so different from single-charge fields.

Electric Potential

Potential V is the work done per unit charge to bring a positive test charge from infinity: V = kQ/r. Equipotential surfaces connect points of equal V. Moving along an equipotential requires no work. Field lines always point from high to low potential � "downhill" in the potential landscape.

Key Equations

QuantitySymbolFormulaUnits
Coulomb forceFkq1q2 / r�N
Electric fieldEF/q = kQ/r�N/C = V/m
Electric potentialVkQ/r = W/qV (volt)
Electric PEUkq1q2/r = qVJ
Coulomb constantk1/(4pe0) � 8.99�10?N�m�/C�
Permittivity of free spacee08.85�10?�� C�/(N�m�)F/m
E from potentialE-?V = -dV/drV/m
Field inside conductorE0N/C

Field Line Rules

Direction

Field lines start on positive charges and end on negative charges (or go to infinity if no negative charge is present). A positive test charge would follow the field line direction.

Density

The density of field lines in a region indicates field strength. Closely-spaced lines = strong field. Widely-spaced lines = weak field. Near a point charge, lines are densest close to the charge.

Never Cross

Field lines can never cross each other. If they did, the field would have two directions at that point � physically impossible. At saddle points between equal charges, field lines approach but never cross.

Perpendicular to Equipotentials

Field lines are always exactly perpendicular to equipotential surfaces. This is because E = -?V � the field points in the direction of steepest potential drop, which is always perpendicular to constant-potential surfaces.

Common Configurations

Electric Dipole

Equal and opposite charges separated by distance d. The dipole moment p = qd. Field lines arch from + to -, forming characteristic cardioid-like loops. At large distances, dipole field falls as 1/r� (faster than 1/r� for a single charge).

Parallel Plate Capacitor

Two rows of opposite charges approximate a parallel plate capacitor. Between the plates, the field is nearly uniform and perpendicular to the plates. Field strength E = s/e0 = V/d in the ideal infinite-plate limit.

Quadrupole

Four charges (+ - + -) arranged at corners of a square. More complex field topology with multiple neutral points. Quadrupole fields fall as 1/r4 at large distances. Used in particle accelerator focusing magnets.

Gauss's Law

The total electric flux through any closed surface equals the enclosed charge divided by e0: ?E�dA = Q_enc/e0. Powerful for symmetric charge distributions � gives E immediately for spheres, cylinders, and planes.

Worked Example

Step 1: Single Charge

A +5 nC charge sits at the origin. Find E and V at r = 0.10 m.

E = kQ/r� = (8.99�10? � 5×10⁻⁹) / 0.01 = 4495 N/C

V = kQ/r = (8.99�10? � 5×10⁻⁹) / 0.10 = 449.5 V

Step 2: Second Charge

A -5 nC charge is placed at (0.20 m, 0). Find E at the midpoint (0.10 m, 0).

From +5 nC: E1 = 4495 N/C pointing right (+x).

From -5 nC: E2 = 4495 N/C pointing right (+x toward - charge).

E_total = 8990 N/C in +x direction.

Step 3: Force on Test Charge

A +1 nC test charge is placed at the midpoint. What force does it experience?

F = qE = 1�10⚡ � 8990 = 8.99�10?6 N (toward -5 nC charge).

Step 4: Potential Energy

V at midpoint: V1 = 449.5 V, V2 = kQ/r = 8.99�10?�(-5×10⁻⁹)/0.10 = -449.5 V.

V_total = 449.5 - 449.5 = 0 V (midplane of dipole is at V=0).

PE of test charge: U = qV = 1�10📚 � 0 = 0 J.

Curriculum Links

LevelTopicKey Concepts Covered
GCSE PhysicsElectrostaticsStatic charge, attraction/repulsion, field lines direction, spark discharge
A-Level PhysicsElectric FieldsCoulomb's law, E = kQ/r�, V = kQ/r, equipotentials, E = -?V/?r, capacitors
IB Physics HLFields (Topic 10)Coulomb force, field strength, potential, work done in field, capacitance
AP Physics CElectrostaticsGauss's law, field from superposition, potential energy, conductors in E fields
University Year 1ElectromagnetismMaxwell's equations (static), multipole expansion, image charges, conductors

Frequently Asked Questions

Why do electric field lines never cross?

If two field lines crossed at a point, the electric field would simultaneously point in two different directions at that point � which is physically impossible. The field at any point is uniquely determined by the superposition of all charges. Crossing would imply the field is multivalued, violating the uniqueness of the Coulomb force.

What happens to field lines inside a conductor?

In electrostatic equilibrium, the electric field inside a conductor is exactly zero. Free electrons rearrange themselves on the surface until the internal field cancels out. All field lines terminate (or originate) on the surface charges. This is why a Faraday cage shields the interior from external fields � and why car bodies protect people from lightning.

How is electric potential energy different from electric potential?

Electric potential V = kQ/r is a property of the field at a point, with units of volts (J/C). Electric potential energy U = qV is the energy stored when a specific charge q is placed at that point. Potential is a property of space; potential energy involves placing a charge in that space. Analogy: gravitational field (g) vs. gravitational PE (mgh).

Why are equioptential lines perpendicular to field lines?

The electric field is mathematically defined as E = -?V (the negative gradient of potential). The gradient of a scalar always points in the direction of maximum increase. Equipotential surfaces are surfaces of constant V, so moving along them changes V by zero � meaning you move perpendicular to the gradient. Therefore E is always perpendicular to equipotentials.

What is the significance of the inverse-square law?

The 1/r� dependence of Coulomb's law (and Newton's gravity) arises from geometry: in 3D space, electric flux spreads over a spherical surface whose area grows as 4pr�. Since total flux is conserved (Gauss's law), field strength must decrease as 1/r�. This 1/r� form is not arbitrary � it is a direct consequence of living in three spatial dimensions.

Related Simulations

Further Reading

🔒 Unlock Premium Features

Unlock movable test particle with trajectory tracing, time-varying charge animation, 3D field rendering, CSV export of field data, and all 32 simulations with MySimulator Premium.