Chemistry · Materials Science
June 2026 · 14 min read · Crystallography · Bravais Lattice · Slip Systems

BCC, FCC & HCP — Crystal Structures of Metals

The mechanical, electrical, and thermal properties of metals are profoundly shaped by how their atoms arrange themselves in space. Iron and steel owe their strength partly to body-centred cubic packing; copper, aluminium, and gold are soft and ductile because of face-centred cubic geometry with its many slip planes; magnesium and titanium adopt hexagonal close-packing. Understanding these structures — their packing efficiency, coordination environments, and deformation mechanisms — is the foundation of materials science and metallurgy.

1. The 14 Bravais Lattices

A crystal is an infinite periodic arrangement of atoms. The underlying periodicity is described by a Bravais lattice — a set of points R = n₁a₁ + n₂a₂ + n₃a₃ where a₁, a₂, a₃ are the primitive lattice vectors and n₁, n₂, n₃ are integers.

Auguste Bravais proved in 1848 that there are exactly 14 distinct lattice types in three dimensions (grouped into 7 crystal systems: cubic, tetragonal, orthorhombic, monoclinic, triclinic, trigonal, and hexagonal). The three cubic Bravais lattices are:

The hexagonal close-packed (HCP) structure is not a Bravais lattice itself but a hexagonal lattice with a two-atom basis — two atoms per lattice point, positioned at (0,0,0) and (⅓, ⅔, ½) in fractional coordinates.

2. Body-Centred Cubic (BCC)

In the BCC structure, atoms occupy the corners of a cube and one atom sits at the geometric centre. The conventional unit cell contains 2 atoms (8 × ⅛ corner + 1 body centre).

Geometry and Atomic Packing Factor

Atoms in BCC touch along the body diagonal. If R is the atomic radius and a is the lattice parameter:

Body diagonal = 4R = a√3 → a = 4R/√3 Volume of 2 atoms per cell: V_atoms = 2 · (4/3)πR³ = (8/3)πR³ Volume of unit cell: V_cell = a³ = (4R/√3)³ = 64R³/(3√3) Atomic Packing Factor (APF) = V_atoms / V_cell APF_BCC = (8πR³/3) / (64R³/3√3) = 8π√3/64 = π√3/8 ≈ 0.6802 = 68.02%

The coordination number (number of nearest neighbours) in BCC is 8 — the body-centre atom touches all 8 corners, and each corner atom touches the body-centre atoms of all 8 surrounding cubes.

There are also 6 next-nearest neighbours at distance a (the face centres of the cube), only 15% further than the nearest neighbours. This near-equal spacing of 1st and 2nd shells influences BCC properties.

BCC Metals

Common BCC metals: Fe (α-iron, below 912°C), W (tungsten — highest melting point of all metals), Mo, Cr, V, Nb, Ta, K, Na, Li.

3. Face-Centred Cubic (FCC)

In FCC, atoms occupy all 8 cube corners plus the centres of all 6 faces. The conventional unit cell contains 4 atoms (8 × ⅛ + 6 × ½).

Geometry and Atomic Packing Factor

FCC atoms touch along the face diagonal:

Face diagonal = 4R = a√2 → a = 2R√2 Volume of 4 atoms: V_atoms = 4 · (4/3)πR³ = (16/3)πR³ Volume of unit cell: V_cell = a³ = (2R√2)³ = 16R³√2 APF_FCC = (16πR³/3) / (16R³√2) = π/(3√2) ≈ 0.7405 = 74.05%

FCC is one of the two close-packed structures (along with HCP), achieving the maximum possible packing fraction for equal spheres (proved by the Kepler conjecture, solved by Hales in 2005).

The coordination number in FCC is 12: each atom is surrounded by 12 equidistant nearest neighbours (4 in the same layer, 4 above, 4 below).

The FCC structure can also be viewed as ABCABC... stacking of close-packed {111} planes. The three layers A, B, C each consist of atoms in a triangular array, offset so each layer nestles in the hollows of the one below.

FCC Metals

Common FCC metals: Cu (copper), Al (aluminium), Ni, Ag (silver), Au (gold), Pt, Pb, γ-Fe (iron above 912°C), Ca, Sr.

FCC metals are generally soft and ductile because the {111} close-packed planes — 4 distinct families of which exist — provide many slip systems for dislocation motion, enabling plastic deformation without fracture.

4. Hexagonal Close-Packed (HCP)

HCP also achieves the 74% maximum packing efficiency (APF ≈ 0.7405) but via a different stacking sequence: ABABAB... rather than ABCABC. Close-packed planes alternate between two positions A and B only, never visiting a third position C.

Unit Cell and Ideal c/a Ratio

The HCP unit cell is a right hexagonal prism with basal plane hexagonal lattice parameter a and height c. It contains 2 atoms. The ideal close-packed geometry requires:

(c/a)_ideal = √(8/3) = 2√(2/3) ≈ 1.6330 This ratio ensures that nearest neighbours in the basal plane (distance a) and nearest neighbours in adjacent planes (distance √(a²/3 + c²/4)) are equidistant — giving CN = 12. Real HCP metals deviate from ideal: Mg: c/a = 1.624 (close to ideal) Zn: c/a = 1.856 (much larger — Zn is oblate-distorted) Ti: c/a = 1.587 (smaller than ideal — prolate-distorted) Be: c/a = 1.568 (smallest common HCP metal)

When c/a differs from ideal, nearest-neighbour distances within the basal plane and between planes are unequal, reducing the effective coordination number and affecting mechanical anisotropy.

HCP Metals

Common HCP metals: Mg, Ti (α-phase), Zn, Co (α-phase), Cd, Zr (α-phase), Be, Ru, Os.

5. Comparison Table

Property BCC FCC HCP
Atoms per unit cell242
Coordination number8 (+6)1212 (ideal)
Atomic packing factor68.02%74.05%74.05%
Lattice parameter (R)a = 4R/√3a = 2R√2a = 2R, c = 2R√(8/3)
Close-packed planes{110}{111}Basal (0001)
Number of slip systems48 (potential)123 (basal)
Stacking sequenceABCABCABABAB
Typical ductilityModerateHighLow (limited slips)
Example metalsFe, W, Cr, MoCu, Al, Au, NiMg, Ti, Zn, Co

6. Miller Indices: Planes and Directions

Crystallographic planes and directions are identified using Miller indices (hkl) for planes and [hkl] for directions. The procedure for planes:

  1. Find the intercepts of the plane on the three crystal axes in units of the lattice parameter
  2. Take the reciprocals of these intercepts
  3. Clear fractions to obtain the smallest integers h, k, l
  4. Enclose in parentheses: (hkl). Negative intercepts denoted with overbars: (h̄kl)
Example: Plane intercepts at x=1, y=2, z=∞ (parallel to z-axis) Reciprocals: 1/1, 1/2, 1/∞ = 1, 0.5, 0 Clear fractions (×2): 2, 1, 0 Miller indices: (210) Key planes in cubic systems: (100): face of the cube, 6 equivalent: {100} family (110): face diagonal plane, 12 equivalent: {110} family (111): body diagonal plane (close-packed in FCC), 8 equivalent: {111} family

For HCP, a four-index notation (hkil) is used, where i = −(h+k), to make the symmetry-equivalent planes more obvious in the hexagonal system.

7. Slip Systems and Plastic Deformation

Plastic deformation in metals occurs primarily by dislocation glide: a line defect (dislocation) moves through the crystal on a slip plane in a slip direction. The combination of a slip plane and slip direction is a slip system.

Slip is energetically easiest on close-packed planes in close-packed directions, because the atoms are densest, the inter-planar spacing is largest (lowest energy to shear), and the Burgers vector (lattice displacement per slip step) is smallest.

FCC Slip Systems

FCC has 4 close-packed {111} planes, each with 3 close-packed <110> directions:

FCC slip systems: {111}⟨110⟩ Number of systems: 4 planes × 3 directions = 12 Burgers vector: b = (a/2)⟨110⟩ |b| = (a/2)√2 = a/√2 12 independent slip systems → Von Mises criterion satisfied → FCC metals can deform in any direction → high ductility (e.g. Cu, Al, Au)

BCC Slip Systems

BCC has no true close-packed planes, but the closest are {110}, {112}, and {123} planes. The slip direction is always <111> (body diagonal, the close-packed direction):

BCC slip systems: {110}⟨111⟩ (6 planes × 2 dirs = 12) {112}⟨111⟩ (12 planes × 1 dir = 12) {123}⟨111⟩ (24 planes × 1 dir = 24) Total potential: 48 slip systems However, the Peierls-Nabarro stress is higher in BCC → harder to activate slip → BCC metals are stronger but less ductile than FCC at room temperature.

HCP Slip Systems

HCP has only one close-packed plane family (the basal plane, {0001}) with three <11̄20> directions, giving just 3 basal slip systems. This is below the 5 independent systems required by the Von Mises criterion for arbitrary shape change, which is why HCP metals (Mg, Zn, Ti) are much less ductile than FCC metals. Additional slip on prismatic {101̄0} and pyramidal {101̄1} planes can activate at high temperatures.

The Von Mises Criterion: For a polycrystalline material to deform without cracking, each grain must accommodate the imposed strain. This requires at least 5 independent slip systems per grain. FCC satisfies this easily (12 systems); HCP with only 3 basal systems does not, limiting formability unless temperature activates additional systems.

8. Why Metals Choose Their Structure

Crystal structure is determined by quantum mechanics — the electronic band structure of each element determines which arrangement of atoms minimises the total energy (kinetic energy of electrons + ion-electron attraction + ion-ion repulsion + electron-electron repulsion). Simple rules of thumb:

Alloying can shift crystal structure preferences: adding carbon to iron expands the FCC (austenite) stability range, which is why steelmakers heat treat steel above 912°C to dissolve carbon in the FCC phase before quenching.

Crystal Structure Simulator
Explore BCC, FCC and HCP packing, rotate unit cells, and visualise slip planes interactively