Cars arrive at random, wait in a queue, and charge on stalls that share one power cabinet. Tap a car for its details. Independent educational model with illustrative numbers.
Question 1: how many stalls can this cabinet and grid connection really feed? Question 2: how much does a buffer battery help on a weak grid connection? Each point is the mean of 3 random days of 6 simulated hours (after a 1 hour warm-up).
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A pack of N series cells has open-circuit voltage Voc(s) = N (3.45 + 0.55 s + 0.2 s³) (4.2 V per cell when full) and internal resistance R = R20 e0.035 (20 - T) (1 + 0.6 e-12 s). The terminal voltage is V = Voc + I R and the power is P = V I. Charging is first limited by current (a C-rate the cells can take, Imax = c Q); once V reaches N × 4.2 V the charger must hold the voltage and the current falls, I = (Vmax - Voc(s)) / R. That is the taper in the power curve. State of charge follows ds/dt = I / (3600 Q) (Q in ampere-hours).
A cold pack has a higher R, so it reaches the voltage ceiling earlier, and lithium plating limits the current, which the model derates linearly from 25 C (full) down to 12 % at -10 C. Above 45 C the current is derated to zero at 60 C. The pack heats by Cth dT/dt = I²R + Pheater - hA (T - Tamb) - Pchiller; below 18 C the car spends up to 8 kW (for a 60 kWh pack) of the connector power on warming the pack, above 33 C a chiller removes heat. Pre-conditioning means arriving at 30 C.
Each stall can deliver at most its rating, and the cabinet at most Pcab. The power available on the DC bus is min(Pcab, ηPgrid + Pbuffer) with η = 0.96. With dynamic sharing the cabinet gives every car min(demand, fair level) (water-filling: small demands are met in full, the rest split equally); static sharing gives each stall a fixed 1/N of the cabinet, which wastes power when some stalls are empty or tapering.
The import is (Pcars - Pbuffer) / η. When the cars ask for more than the grid can give, a buffer battery of size E (up to 1C, 96 % each way) covers the difference until it is empty; when demand is lower it recharges from the spare connection. A buffer therefore helps with short peaks, not with an average demand that exceeds the connection.
Cars arrive as a Poisson process with rate λ. With c stalls, mean service time 1/μ and load ρ = λ / (c μ) < 1, the Erlang C formula gives the probability of waiting C(c, a) = [ac/c! · 1/(1-ρ)] / [∑k<c ak/k! + ac/c! · 1/(1-ρ)], a = λ/μ, and the mean wait Wq = C / (c μ - λ). Here the service time is not fixed: it depends on the car, the temperature and on how many other cars share the cabinet, so the simulated wait grows earlier than Erlang C predicts when power is the bottleneck. A queue limit makes cars give up (balk) when too many are waiting.
Revenue = kWh at the connector × your price; cost = grid kWh × energy price + a demand charge on the connection (£ per kW per month, spread over hours). Pure illustration, not a tariff.
Independent educational model, not affiliated with or endorsed by any company named here; trademarks belong to their owners. Numbers are textbook-level/publicly reported approximations.