Presets
Playback
Parameters
Camera
Layers
Quality
Model check
The science
Model. n = 1 mol of an ideal gas (p V = nRT) with constant heat capacities, gamma = 7/5 (air) or 5/3 (helium), runs the four reversible strokes of the Carnot cycle: isothermal expansion at TH (V2 = rV1), adiabatic expansion along T Vγ−1 = const, isothermal compression at TC, adiabatic compression back to V1. The heats are QH = nRTH ln r and QC = nRTC ln r (because V3/V4 = V2/V1), so W = QH − QC and η = 1 − TC/TH, independent of the gas and of r. In reverse the same loop is a refrigerator (COP = TC/(TH−TC)) or heat pump (TH/(TH−TC)).
Why no real engine reaches it. A reversible stroke takes infinite time. The finite-time (endoreversible) model gives the working fluid temperatures Th′ < TH and Tc′ > TC to drive heat at rate kΔT; with QH′/Th′ = QC′/Tc′ the power peaks at ηCA = 1 − √(TC/TH) (Curzon-Ahlborn 1975), which is close to what power stations achieve. The third graph is that power against efficiency.
Simplifications. The cycle is driven quasi-statically along the exact curves; the cycle time slider only scales the animation. The molecular swarm is a visual aid: its speed is rescaled to the temperature the thermodynamics demands (it is not what computes the numbers), and the piston drawing uses a linear height-volume map between V1 and V3. Friction, leakage and heat conduction through the cylinder wall are ignored.
Checks. (1) the numerical loop integral of p dV equals QH − QC and W/QH = 1 − TC/TH; (2) the closed integral of dQ/T along the path is zero (this also tests the adiabat exponent); (3) a molecular-dynamics piston compressing 2000 particles reproduces the adiabat law T Vγ−1 = const; (4) the scanned maximum-power efficiency equals 1 − √(TC/TH).