Presets
Playback
Throw
Release speed, aim, spin and ice condition decide where the stone ends.
Model checks
The science
What is modelled
A full curling sheet (4.75 m wide, hog line to hog line 21.95 m, 12-foot house) and 19.1 kg granite stones. You choose the release speed, aim and spin; the stone then glides on pebbled ice, curls, can be swept, and can hit the stones already in play. Eight stones make an end; the model scores it the way the rules do (stones in the house closer to the button than the opponent's best).
Equations
- Friction on pebbled ice falls with speed:
μ(v) = μ1 / √v, decelerationa = μ g. Thenv3/2decreases linearly in time, the stone stops aftert = v03/2 / (1.5 μ1 g)and travelsx = 0.4 v05/2 / (μ1 g). With μ1 = 0.0125 a hog-line release of 2.4 m/s reaches the far tee. - Sweeping warms the ice film and lowers friction:
μ → μ (1 − 0.2 s), so full sweeping lets the same stone travel 25 % farther. - Curl: a clockwise stone drifts right, a counter-clockwise one left. The model uses a sideways acceleration
alat = c μ g tanh(ω/0.3) (1 − 0.35 s)perpendicular to the motion. - Spin decays by
dω/dt = −0.1 μ g rb / k2with running-band radius rb = 0.065 m and radius of gyration k = 0.1 m. - Stone-stone hits: equal masses, smooth contact, normal restitution e = 0.85:
J = (1+e) m vn / 2and kinetic energy loss(1 − e2) m vn2 / 4. The tangential motion is untouched.
Checks run in the page
- Stopping distance and time of a spinless stone against the closed forms.
- Work-energy theorem (friction work equals the initial kinetic energy).
- Sweeping extends the run by exactly 1/0.8.
- Collision: momentum, tangential speed and the kinetic-energy loss formula.
- Curl mirror symmetry and the number of turns.
Honest simplifications
- Why a curling stone curls is still debated in the research literature (pivot-slide, scratch-guide and thin-film models); the sideways force here is an empirical law tuned to about 1 m of curl on a draw, not a derivation from first principles.
- The 1/√v friction form, the 20 % sweeping effect, the spin-decay coefficient and e = 0.85 are fitted, representative values; real ice varies with pebble, temperature and the stone's own running band.
- Stones are 2D discs with no tangential contact friction, so spin is not transferred in a hit.
- The release is from the near hog line; the delivery slide is not modelled.
What to try
- Throw a draw with the default settings, then press Aim at button after changing spin or ice: the aim is solved by bisection on the same physics.
- Hold the sweep button while the stone is between the hog lines: sweeping cuts friction by up to 20 percent and keeps the stone straighter and longer.
- Throw two stones at the house and a fast takeout: the collision loses energy as (1 - e squared) times the normal relative speed squared over four.