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Apparatus
Model checks
The science
What is modelled
A circle of radius R, centred slightly left of and above the origin, is placed in a uniform stream at angle alpha. The Joukowski map w = z + a²/z turns this circle into an airfoil with a sharp tail at z = a. The flow past a circle is known exactly, so the flow past the airfoil follows by conformal mapping.
Equations
- Complex potential in the circle plane
W = U (ζ e-iα + R² eiα / ζ) + (i Γ / 2π) ln ζ, with ζ measured from the circle centre. - Kutta condition (finite velocity at the tail)
Γ = 4 π U R sin(α + β), where sinβ = camber rise / R. - Physical velocity
u − i v = (dW/dζ) / (dw/dz), pressure coefficientCp = 1 − |V|² / U². - Lift per span
L' = ρ U Γ(Kutta-Joukowski),CL = 2 Γ / (U c).
Checks run in the page
- Velocity at the trailing-edge point of the circle is zero.
- The numerical line integral of velocity around a loop equals the Kutta circulation.
- The lift from integrating Cp around 720 surface panels equals the circulation lift, and the pressure drag is zero.
- The highest surface pressure coefficient is exactly 1 at the stagnation point.
Honest simplifications
The flow is inviscid, steady, incompressible and two-dimensional. There is no boundary layer, no stall, no drag and no wake, and the lift keeps growing with angle where a real wing would stall. The chord is taken as 1 m only to give the lift a number in newtons per metre of span. Thickness and camber are the Joukowski parameters, not a standard wing section.
What to try
- Choose Symmetric, zero lift: the lift vanishes at zero angle and the surface pressure curves of the two sides coincide.
- Choose High lift: the suction peak near the leading edge deepens as the angle and camber rise.
- Raise the speed and watch the lift grow with its square in the third plot.