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The science
What is modelled
A horizontal double-acting steam engine of the kind that drove mills: a 0.32 m bore, 0.6 m stroke cylinder, a crosshead and connecting rod, a heavy flywheel, a slide valve and a flyball governor. Steam from the boiler is admitted at one end of the cylinder, shut off at the cut-off point and then expands, pushing the piston; on the return stroke the same face is open to the exhaust. The other face does the same half a turn later. The engine torque is worked out from the pressure on both faces and the crank geometry, and drives a flywheel that turns a fan-type load.
Equations
- Crank-slider: crosshead position
X = r cosθ + √(l² − r² sin²θ), so the piston displacement from head-end dead centre iss = X(0) − X(θ)andds/dθ = r sinθ (1 + r cosθ / √(l² − r² sin²θ)). - Pressure on a face:
p = pbuntil the stroke fraction reaches the cut-off, thenp = pb (Vc/V)n(polytropic expansion, n about 1.135 for wet steam), then the exhaust pressure on the return stroke. - Work per face per revolution:
W = pb(Vc − V0) + (pbVc − pxVe)/(n − 1) − pe(Ve − V0); the crank-end face uses the annulus (piston area minus rod area). - Torque on the crank (virtual work):
T = Fs ds/dθwithFs = pHEA − pCE(A − Arod) − patmArod. - Flywheel:
I dω/dt = T(θ) − kω² − Tf, withI = m R²of the rim plus a small rotor term. The speed ripple follows the energy rule(ωmax − ωmin)/ω ≈ (Emax − Emin)/(Iω²). - Governor (Watt): a ball on an arm of length L on a spindle at ωs hangs at
cosφ = g/(ωs² L). In governor mode the cut-off followsc = c0 + K(ωset − ω), a proportional controller that leaves a speed droop under load. - Steam used: the cylinder volume up to cut-off times the saturated steam density (ideal-gas value at the saturation temperature of the Antoine equation).
Checks run in the page
- Kinematics: analytic
ds/dθagainst a central difference, rod length constant, stroke exactly 2r. - Work per revolution from integrating the crank torque (40000 steps) against the closed polytropic formula, for three steam conditions.
- Steady-state speed of the integrated flywheel equation against the torque balance
ω = √((Tm − Tf)/k). - Speed fluctuation against the energy formula.
- A damped swinging governor ball against
arccos(g/(ω²L)).
Honest simplifications
- No compression of the trapped exhaust steam, no pre-admission (lead), no pressure drop through the ports and no heat exchange with the cylinder walls. Real engines lose a large part of their steam to initial condensation on the cold walls, so real consumption per kWh is higher than the figure shown, and real indicator diagrams have rounded corners.
- The expansion exponent is a single constant; the slide valve is drawn schematically (it follows the admission state; no eccentric or valve-gear geometry, lap or lead).
- The flywheel, bearings and guides are lumped into one moment of inertia and a constant friction torque; the rod and crosshead masses and the oscillating inertia forces are neglected. The load is an idealised fan law.
- The governor is shown as a Watt governor with a proportional response; real governors have friction, dead zone and can hunt. The boiler is a constant-pressure source. Dimensions and coefficients are illustrative, not a particular historic engine.
What to try
- Compare cut-off 0.2 and 0.7: the work per revolution rises, but the steam used per kWh rises faster.
- Use "Condensing": the low exhaust pressure raises the work for the same boiler pressure.
- Switch on the governor and press "Load step": the speed dips, the cut-off opens, and the speed settles with a droop.
- Reduce the flywheel mass to 500 kg and watch the speed ripple in the third graph.
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