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Water, wheel and hammers
The water supplies a power that the wheel turns into torque falling with speed; each cam lifts a hammer for 70 degrees of shaft turn.
Model checks
The science
What is modelled
An overshot wheel supplies the power eta rho g Q H; its torque falls linearly with speed. Cams on the shaft lift hammers and let them drop on the cloth. The shaft obeys I dw/dt = torque of the wheel - cam torque - bearing drag.
Equations
- Power available
P = eta rho g Q H, maximum at half the free-running speed; stall torque4 P / w_f. - Cam torque
m g dh/dthetawhile a cam lifts a hammer byh(theta) = lift (1 - cos(pi s)) / 2. - Work per turn
N m g h; blows per secondN w / 2 pi. - Drop
t = sqrt(2h/g), impact speedsqrt(2 g h).
Checks run in the page
- Power curve scanned for its maximum.
- Cam work per turn against the lifted potential energy.
- Time-stepped steady speed against the torque balance and counted blows.
- Free fall and impact energy per blow.
Honest simplifications
Linear wheel characteristic, cam lift of 70 degrees, hammers lifted by their centre of mass without lever ratio, a flywheel inertia of 6000 kg m2 and bearing drag of 80 N m s are assumed values; stock-to-cloth friction and water level changes are not modelled.
What to try
- Press Weak stream, heavy hammers: the wheel slows at every cam and may stall.
- Press Flood: strong flow to see the wheel run near its free speed.
- Add hammers with the slider and watch the torque ripple smooth out.