⚗️ Reaction Order Detective — initial rates, half-lives, Arrhenius
Presets
Reaction
Your guess:
Live readouts
Experiments
Run an experiment: results are compared with the true value.
The science
Rate law
d[A]/dt = −k[A]n. Integrated: n=0 → [A]=[A]0−kt; n=1 → [A]=[A]0e−kt; n=2 → 1/[A]=1/[A]0+kt. The plot that comes out straight (a different one for each order) identifies n.
Half-life
n=0: t½=[A]0/2k; n=1: t½=ln2/k (independent of [A]0); n=2: t½=1/(k[A]0). So t½(2[A]0)/t½([A]0) = 21−n.
Initial rates
Rate0=k[A]0n, so the slope of log(rate) vs log[A]0 is n.
Arrhenius
k=k298·exp[−(Ea/R)(1/T−1/298.15)], R=8.314 J/(mol·K); the slope of ln k vs 1/T is −Ea/R.
Molecule view
N0=300 molecules; each time step the number of reactions is drawn from a Poisson distribution with mean (rate × dt), so the jagged trace scatters around the smooth curve (fewer molecules = more noise). Molecule motion is decorative (it speeds up with √T) and does not itself determine the rate.
Simplifications and honesty
Single-step irreversible reaction, constant volume, perfectly mixed, no reverse reaction. Zero order is realised in real life when a catalyst surface is saturated; here it is simply defined. Measurement noise in the experiments (3% on rates, 2% on k) is added on purpose to mimic a lab and is not a chemical effect. Rate constants are illustrative, not data for a named reaction.
Independent check
The exact curve is the closed form above; a separate RK4 integration of the differential equation is compared against it live (relative error shown in the readouts).