kH(T) = mol/(L·atm)
Equilibrium Ceq = kH·p = g/L
Dissolved C now = g/L
Gas released = mL CO₂ (at 1 atm, T)
Independent check
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Equations
Ceq = kH(T)·p, kH(T) = kH°·exp[d(1/T − 1/298.15)], kH°=0.034 mol/(L·atm), d=2400 K, M=44.01 g/mol.
dC/dt = −k(C − Ceq): relaxation toward equilibrium.